STAT/MATH 394B

Solutions, homework 6

1.2.1 (a) ={SSS,SSF,SFS,FSS,SFF,FSF,FFS,FFF} or {111,112,113,...,665,666}

P(SSS)=(1/3) x (1/3) x (1/3) ... P(FFF) = (2/3) x (2/3) x (2/3)

(b) pX(0) = P(FFF) = 8/27 from (a)

pX(1) = 3 x (1/3) x (2/3) x (2/3) = 12/27

pX(2) = 3 x (1/3) x (1/3) x (2/3) = 6/27

pX(3) = 1/27

(c) P(X„1) = 1 - P(X = 0 ) = 19/27

1.2.10 (a) P(X = 2 , 4 or 6 ) = 4/91 + 16/91 + 36/91 = 56/91

(b) P ( X <= 2 ) = 1/91 + 4/91 = 5/91

(c) P(X = 1 or 4 ) = 1/91 + 16/91 = 17/91 (here I read "perfect square" to mean "square")

1.2.14 (a) Yes. and w2>0.

(b) so and (27/8)p(w) is a pmf.

(c) so (1/9)p(w) is a pmf.

(d) which cannot be rescaled into a pmf.

(e) so (2/N(N+1))p(w) is a pmf.

(f) so (3/4)p(w) is a pmf.

(g) which cannot be rescaled into a pmf.

(h) Since some terms are positive and some are negative, this cannot be a pmf.

3.1.7 (a) From 1.2.14 (a) the mass function is x2/55.

(b) P(1<X <= 3) = P (X = 2 or 3) = (4+9)/55 =13/55.